Express each number as a product of its prime factors: (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

Solution:

(i) 140

By a long division of 140, we will get the product of its prime factor.

Product of prime factors of 140 = 2 × 2 × 5 × 7 × 1 = 22 × 5 × 7

(ii) 156

By a long division of 156, we will get the product of its prime factors.

Product of prime factors of 156 = 2 × 2 × 13 × 3 × 1 = 22 × 13 × 3

(iii) 3825

By a long division of 3825, we will get the product of its prime factors.

Product of prime factors of 3825 = 3 × 3 × 5 × 5 × 17 × 1 = 32 × 52 × 17

(iv) 5005

By a long division of 5005, we will get the product of its prime factors.

Product of prime factors of 5005 = 5 × 7 × 11 × 13 × 1 = 5 × 7 × 11 × 13

(v) 7429

By a long division of 7429, we will get the product of its prime factors.

Product of prime factors of 7429 = 17 × 19 × 23 × 1 = 17 × 19 × 23