Solution:
The first multiple of 4 that is greater than 10 is 12.
The next multiple will be 16.
Therefore, the series formed as;
12, 16, 20, 24, …
This an AP with the first term as 12 and a common difference as 4.
When we divide 250 by 4, the remainder will be 2. Therefore, 250 − 2 = 248 is divisible by 4.
The series is as follows, now;
12, 16, 20, 24, …, 248
Let 248 be the nth term of this AP.
First term, a = 12
Common difference, d = 4
an = 248
As we know,
an = a + (n − 1)d
248 = 12 + (n – 1) × 4
236/4 = n – 1
59 = n – 1
n = 60
Therefore, there are 60 multiples of 4 between 10 and 250.