**Solution:**

We know that for an AP;

a_{n} = a + (n − 1) d

a_{17} = a + (17 − 1) d

a_{17} = a + 16 d

In the same way,

a_{10} = a + 9d

As per the given,

a_{17} − a_{10} = 7

Therefore,

(a + 16d ) − (a + 9d) = 7

7d = 7

d = 1

Therefore, the common difference is 1.