The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

Solution:

We know that for an AP;

a_n = a + (n − 1) d

a₁₇ = a + (17 − 1) d

a₁₇ = a + 16 d

In the same way,

a₁₀ = a + 9d

As per the given,

a₁₇ − a₁₀ = 7

Therefore,

(a + 16d ) − (a + 9d) = 7

7d = 7

d = 1

Therefore, the common difference is 1.